Often teachers want to know: how large is the electron deflection $\Delta y$ at the end of the plate capacitor? This question can be answered with the formula derived from the equations of motion:$${y(x)=\frac{V_{\text p}}{4\cdot \text{d}\cdot V_{\text a}}\cdot x^2}\qquad (1)$$
## Task:

Calculate the electron deflection $\Delta y_1$ when leaving the electric field.

**Given:**

Acceleration Voltage V_{a} = 5 kV

Plate Voltage V_{p} = 2 kV

Plate Distance d = 6 cm

Length of Capacitor l = 12 cm

Acceleration Voltage V

Plate Voltage V

Plate Distance d = 6 cm

Length of Capacitor l = 12 cm