## Task: Determine the second lattice spacing of graphite.

Enter different pairs of values in the table at the end of the page. The table calculates the second latice spacing $$d_2$$ using
$m_\text e=9{,}1\cdot 10^{-31}\,\text{kg}$; $e=1{,}6\cdot 10^{-19}\,\text{C}$; $h=6{,}6\cdot 10^{-34}\, \text J \cdot \text s$; $d=2{,}13\cdot 10^{-10}\, \text m$; $L=12{,}7\,\text {cm}$; $R=6{,}35\,\text {cm}$

Voltage $$V_{\rm{a}}$$ $$\lambda_{\rm{de-Broglie}}$$ Radius $$r_{\rm{outer}}$$ $${d_2=\frac{\lambda_{\text{de Broglie}}}{2\cdot \sin\left(\frac{1}{2}\cdot \tan^{-1}\left(\frac{r}{L-R+\sqrt{R^2-r^2}}\right)\right)}}$$
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Mittelwert: $$-$$